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piffle    
vi. 做无聊事,讲废话
n. 傻事,废话

做无聊事,讲废话傻事,废话

piffle
n 1: trivial nonsense [synonym: {balderdash}, {fiddle-faddle},
{piffle}]
v 1: speak (about unimportant matters) rapidly and incessantly
[synonym: {chatter}, {piffle}, {palaver}, {prate}, {tittle-
tattle}, {twaddle}, {clack}, {maunder}, {prattle}, {blab},
{gibber}, {tattle}, {blabber}, {gabble}]
2: act in a trivial or ineffective way

Piffle \Pif"fle\, n.
Act of piffling; trifling talk or action; piddling; twaddle.
[Dial. or Slang] "Futile piffle." --Kipling.
[Webster 1913 Suppl.]


Piffle \Pif"fle\, v. i. [imp. & p. p. {Piffled}; p. pr. & vb. n.
{Piffling}.]
To be sequeamish or delicate; hence, to act or talk
triflingly or ineffectively; to talk nonsense or about
trivial matters; to twaddle; piddle. [Dial. or Slang]

Syn: chatter, palaver, prate, tittle-tattle, twaddle, clack,
maunder, prattle, gibber, tattle, blabber, gabble.
[Webster 1913 Suppl. WordNet 1.5]

2. To act in a trivial or ineffective way.
[WordNet 1.5]


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  • differential topology - How can there be topological 4-manifolds with . . .
    Alexander's horned sphere is a topological sphere in 3-space that cannot be "ironed out", otherwise we would get a smooth (or PL) 2-sphere having a complementary region which is not simply-connected, a fact which is excluded because every smooth (or PL) 2-sphere in 3-space is standard
  • Intuition behind Alexander duality - MathOverflow
    I read Alexander duality as saying "If you have any type of doughnut in a sphere, then the outside must have handles or islands that fill the doughnut's holes " The proof that Ryan outlines exactly matches this intuition
  • What are some mathematical sculptures? - MathOverflow
    It was left to the blind mathematician Bernard Morin to devise a procedure to turn a sphere inside out that could actually be implemented (if the membrane is able to pass through itself, that is ) A sculpture by Gideon Weisz of an approximation of Alexander's horned sphere to five levels
  • gt. geometric topology - Can the Alexander horned sphere arise as a cell . . .
    The Alexander horned sphere is topologically a sphere -- it's only the embedding of the sphere in $\mathbb {R}^3$ that makes it special Is the given CW complex embedded in $\mathbb {R}^3$?
  • Homotopy of the complement of the Alexander Horned Ball
    The Alexander horned ball construction gives a closed embedding from the ball into the sphere, $D^3 \hookrightarrow S^3$ Its complement has zero homology but has a non-trivial $\pi_1$
  • Jordan Curve Theorem for Manifolds - MathOverflow
    Alexander's horned sphere (Wikipedia) shows that even when the first part of your conjecture (1) holds, you cannot expect the second part to The horned sphere is a continuous embedding $\mathbb S^2 \to \mathbb S^3$ that does separate $\mathbb S^3$ into two pieces, one of which is homeomorphic to the open ball
  • differential topology - When a homeomorphism is a diffeomorphism w. r. t . . .
    Namely any smooth involution has a fixed point set which is locally a smooth submanifold, but if an Alexander horned sphere was locally a smooth submanifold (for some smooth structure) then it would have a normal bundle (which is trivial as it is orientable), and $\pi_1 (S^3)$ would be isomorphic to the free product of the two components of the
  • gn. general topology - Subsets of $\mathbb {S}^n$ fixed by an . . .
    Recall that R H Bing was the first to produce exotic involution of S^3 having wild fixed points In particular, he showed that AH $\cup_ {id}$ AH is homeomorphic to S^3, where AH denotes the crumpled 3-cube bounded by the Alexander horned sphere One may have more examples by requiring that the crumpled cubes satisfy the Disjoint Disk Property
  • at. algebraic topology - deformation retraction of the complement . . .
    Let $X$ be a topological space and $V$ and $N$ are subspaces of $X$ It is known that if $V$ is homotopy equivalent to $N$ then $X-V$ need not be homotopy equivalent to $X-N$, the Alexander horned sphere is an example
  • Isotopy class of closed 2-ball embedded in R^3 - MathOverflow
    Very good observation! Simple topological questions always seem to result in some pathological counterexample that redefines our intuition Since the complement of the usual disk is simply connected while the complement of the Alexander Horned Sphere (AHS) is not, the next question would be, is the homotopy type of the complement of an embedding an isotopy invariant? It appears so This only





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